Even if I remove ^ the command doesn't work. Therefore, the output highlights the following results: if. The result shows all instances where the letter i appears followed by an f in the. The regex searches for the character string. The /d, /u, and /l modifiers are not likely to be of much use to you, and so you need not worry about them very much. Only a few characters (all of them being ASCII. Run the following command to test how grep regex works: grep if. /d, /u, /a, and /l, available starting in 5.14, are called the character set modifiers they affect the character set rules used for the regular expression. Otherwise, if you are using Bash, the GNU project’s shell, you can represent these characters via ANSI-C quoting. The proposed solutions search only for pattern which start at the beginning of the line if I interpret the proposed solution correctly. A sequence of non-metacharacters matches the same sequence in the target string, as we saw above with m/abc/. If you are using the -P ( -perl-regexp) option, PCREs give you several ways to do this. ![]() The other approach, labeled Thompson NFA for reasons that will be explained later. Grep: ein nicht geschütztes ^ oder $ wird mit -Pz nicht unterstützt Notice that Perl requires over sixty seconds to match a 29-character string. Perl Regular Expression Character Classes. Root:/tmp# grep -Pzo "^begin\$(.|\n)*^end$" file A string can contain ASCII, UNICODE and escape sequences characters such as n. which is something like grep: a not protected ^ or $ is not supported with -Pz. The proposed grep solutions of the other question don’t work (with Ubuntu?): grep: ein nicht geschütztes ^ oder $ wird mit -Pz nicht unterstützt. The solution doesn’t work in my case but would work in the case of the other question. We can use this command to find all non-ASCII characters: grep -color 'auto' -P -n ' \x80-\xFF' sample.txt. Here, we’ll focus on the most widely used GNU grep. The question asks for a solution with grep which is answered already in the question: grep -A9 if my_file | grep -B9 endif. It is available on almost every Linux distribution system by default. ![]() Has somebody an idea, maybe not with grep?ĭifference to How do I grep for multiple patterns on multiple lines? The option -m1 in the second grep doesn’t help. This is similar in nature to the UNIX grep command, but more powerful as the pattern can be any legal perl function. This doesn’t works if the “if” clause is larger than 9 and if several “if” clauses are in the same file and if the first grep command contains several “if” clauses. File::Grep mimics the functionality of the grep function in perl, but applying it to files instead of a list. I can do this with grep -A9 if my_file | grep -B9 endif. I am on Ubuntu 16.04 and I want to search files for let’s say “if” and I want to the output until “endif”.
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